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Chemistry, 12.04.2021 22:40, hannamcbrayer1
How many grams of oxygen (O2) is required to burn 28.8 g of ammonia (NH3)?
4NH3 + 7O2 → 4NO2 + 6H2O
Molar Masses
NH3=17.0305 g/mol
O2=31.998 g/mol
NO2=46.0055 g/mol
H2O=18.0153 g/mol
a)15.3 g
b)94.9 g
c)54.1 g
d)108 g
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Answers: 2
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How many grams of oxygen (O2) is required to burn 28.8 g of ammonia (NH3)?
4NH3 + 7O2 → 4NO2 + 6H2O...
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