For the concentration cell, Pb(s) | PbSO4(s), NH4+ (3.0M), SO42-(1.50M), NO3- (0.10M), Pb2+(? M) || Pb(NO3)2(0.05 M) | Pb(s), Ecell = -(0.0257/2)ln(x/0.05), what is the expression for x in terms of Ecell ? {The notation used here is exp[x] = ex where "e" is the base of natural logarithm.}

false

because it does not have the potential to be entirely used up

answer : third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol

explanation :

let us write down the given equations

equation 1 :

equation 2 :

equation 3 :

let us use hess's law to find out which 2 equations can be added to get the third equation.

let us reverse equation 2 and multiply it by 2. the new equation that we get is,

equation 4 :

let us add equation 1 & 4

the above equation is similar to equation 3 but has different value for dhrxn.

therefore third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol