2. The diagram shows a Zn/MnO2-KOH alkaline dry cell. In your response, do the following:
• Label all parts.
• Label the cathode and the anode, including the charges on each.
• Show the flow of electrons.
• Explain how the cell works. Include the oxidation and reduction half-reactions in your explanation.

1. Graphite rod (cathode)

2. Positive terminal

3. Solid zinc layer (anode)

4. Paste (reduction takes place here)

5. Negative terminal

Explanation:

This was the only thing i could find on it. hope this helps.

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j