If 175.6 joules of energy are applied to a sample of Aluminum and its temperature changed by 35.4 degrees then what was the weight of the Aluminum sample?

5.51g

Explanation:

Using the following formula:

Q = m × c × ∆T

Where;

Q = amount of heat in Joules

m = mass/weight of Aluminum

c = specific heat of Aluminum (0.900 J/g°C)

∆T = change in temperature.

Based on the information given in this question, Q = 175.6 joules, ∆T = 35.4°C, c = 0.900 J/g°C.

Using, Q = m × c × ∆T

175.6 = m × 0.900 × 35.4

175.6 = 31.86m

m = 175.6/31.86

m = 5.51g

The weight of the aluminum sample is 5.51g.

3 1/4 %

explanation: