A gas at a temperature of 300 K occupies a 5 L flexible container at a pressure of 150 kPa. What volume will it occupy at STP?

6.73 L

This one requires the combined gas law.

P1V1/T1 = P2V2/T2

P1 = 150 kPa = 1.48 atm

V1 = 5 L

T1 = 300 K

P2 = 1 atm

V2 = This is what we’re solving for.

T2 = 273 K

P2 and T2 are based on the conditions of STP. I also changed P1 to atm to keep the units consistent.

Solve the equation for V2:

V2 = P1V1T2 / T1P2

V2 = (1.48 atm)(5 L)(273 K) / (300 K)(1 atm) = 6.73 L

hope this

explanation:

covalent bonds

consist of pairs of electrons shared by two atoms, and bind the atoms to fixed orientation and requre high energies to break them

ionic bonds

when two atoms differ considerably in their electronegativity, then one of the atoms will lose its electron to the other atom. this results in a positively charged ion(cation) and a negatively charged ion (anion)