Using the values of standard enthalpy of formation
NH3 = -46.19 KJ/mol
N2H4 = 95.40 KJ/...
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Chemistry, 07.04.2021 20:20, saucydolphin20p6x92l
Using the values of standard enthalpy of formation
NH3 = -46.19 KJ/mol
N2H4 = 95.40 KJ/mol
H2O = -285.83 KJ/mol
determine the standard enthalpy of formation for the reaction
4NH3 + O2 --> 2 N2H4 + 2 H2O
the sum of reactants is KJ/mol
the sum of products is KJ/mol
The heat of formation is KJ/mol
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