Part 1. A chemist reacted 15.0 liters of F2 gas with NaCl in the laboratory to form Cl2 and NaF. Use the ideal gas law equation to determine the mass of NaCl that reacted with F2 at 280. K and 1.50 atm.

F2 + 2NaCl → Cl2 + 2NaF

Part 2. Explain how you would determine the mass of sodium chloride that can react with the same volume of fluorine gas at STP.

1)  57.27g NaCl

2)  1.34 L NaCl

Explanation:

1) n = pv/rt

   n = 1.5atm (15L) / .0821 (280k) = .98 mol NaCl

   NaCl = 22.99g Na + 35.45g Cl = 58.44g NaCl

   58.44g NaCl x .98 mol NaCl = 57.27g NaCl

2) 15 L F2 = 1 mol F2 / 22.4 L F2 x 2 L NaCl / 1 L F2  = 30 / 22.4 = 1.34 L NaCl

the correct answer is option d

explanation:

i was wrong its d because they dont use cm when calculating square roots