How many particles of ZnCrO4 are present in a 4.5 mole sample?

2.7 × 10²⁴ particles ZnCrO₄

General Formulas and Concepts:

Chemistry

Atomic Structure

MolesAvogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Stoichiometry

Using Dimensional AnalysisExplanation:

Step 1: Define

[Given] 4.5 mol ZnCrO₄

[Solve] particles ZnCrO₄

Step 2: Identify Conversions

Avogadro's Number

Step 3: Convert

[DA] Set up:                                                                                                      [DA] Multiply [Cancel out units]:                                                                      

Step 4: Check

Follow sig fig rules and round. We are given 2 sig figs.

2.7099 × 10²⁴ particles ZnCrO₄ ≈ 2.7 × 10²⁴ particles ZnCrO₄

No table found. the question asks for covalent bond based on electronegativies