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Chemistry, 06.04.2021 23:10, Samuelgamboe
Phosphorous-32 (P-32) decays to sulfur-32 (S-32) with a half life of 14 days. What fraction of the original amount of P-32 will remain after 42 days?
Group of answer choices
1/8 of the original amount
1/2 of the original amount
1/16 of the original amount
1/4 of the original amount
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Answers: 2
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Phosphorous-32 (P-32) decays to sulfur-32 (S-32) with a half life of 14 days. What fraction of the o...
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