4. if 62.8 g ca react with 92.3 g hcl according to the reaction below, how many grams of hydrogen gas will be produced, and how many grams of the excess reactant will be left over?

unbalanced equation: ca + hcl → cacl2 + h2

be sure to show all of your work.

you very much to who ever me with this (:

The balanced chemical reaction is as follows:

 Ca + 2HCl → CaCl2 + H2

We are given the amount of reactants to be used for the reaction. We first need to determine the limiting reactant before proceeding to calculations. We do as follows:

62.8 g Ca (1 mol / 40.08 g) = 1.57 mol
92.3 g HCl (1 mol / 36.46 g ) = 2.53 mol

Therefore, the limiting reactant is hydrochloric acid since it is the one being consumed completely in the reaction.

2.53 mol HCl ( 1 mol H2 / 2 mol HCl ) ( 2.02 g/ 1 mol) = 2.56 g H2 produced

1.57 mol Ca - (2.53 mol HCl)( 1 mol Ca / 2 mol HCl ) = 0.305 mol Ca left
0.305 mol Ca ( 40.08 g / 1 mol) = 12.22 g Ca left

The kinetic energy of the liquid increases. hope this !