17. What is the molarity of ZnCl2 that forms when 15 grams of Zn reacts completely with CuCl, if a final volume of 175 mL is produced?
Zn + CuCl2 → ZnCl2 + Cu

1.31M

Explanation:

Based on the reaction, 1 mole of Zn produce 1 mole of ZnCl₂. As the reaction occurs completely, the moles of Zn added = Moles of ZnCl₂ produced. To find molarity we need the moles of ZnCl₂ and the volume of the solution in liters:

Moles Zn = Moles ZnCl₂ -Molar mass Zn: 65.38g/mol-:

15g * (1mol / 65.38g) = 0.23 moles of ZnCl₂

Volume in Liters:

175mL * (1L / 1000mL) = 0.175L

The molarity is:

0.23moles / 0.175L

1.31M

The answer is celsius 

The problem here is that according to aufbau principle before 3d orbital 4s subshell comes.after filling 3p orbital with electrons you have 4 electrons left, you place two in 4s with opposite spin and the other two in 3d in any of its two orbitals of total five orbitals with the same spin.