Mass of a crucible = lo grams. Mass of a crucible and soil before heating 29 grams. Mass
of a crucible and soil after heating = 18 grams
From the information above, determine the Percentage of water in the given soil sample?
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c. heat could easily travel through the molecules in the air and escape/enter the flask. removing the air slows down the heat transfer.  

it is a solid

explanation:

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percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally