How many liters of nitrogen gas (N₂) are required to produce 7.5 x 10²⁶ molec NH₃ gas with excess of hydrogen gas at STP?

The volume of nitrogen gas that is required is 13944 L.

Explanation:

Given values:

Number of molecules of ammonia gas =

According to the mole concept:

number of molecules are present in 1 mole of a compound

So, number of molecules will be present in of ammonia gas

The chemical equation for the formation of ammonia gas follows:

According to the stoichiometry of the reaction:

2 moles of ammonia gas are produced from 1 mole of nitrogen gas

So, moles of ammonia gas will be produced from moles of nitrogen gas

At STP conditions:

1 mole of a gas occupies 22.4 L of volume

So, moles of nitrogen gas will occupy of volume

Hence, the volume of nitrogen gas that is required is 13944 L.

nacl or sodium chloride is an ionic compound. this is because an ionic compound pertains to a compound that consists of positively and negatively charged ions. in this case, na (sodium) has a tendency to lose one electron when it reacts with with other atoms, so the resulting sodium ion contains 11 protons and 10 electrons, thus making it positively charged (na+), when chlorine reacts, it usually gains one electron to form an ion called chloride, thus making it negatively charged ( since the ions are oppositely charged, they attract.