5.
Cr(NO3)3 (aq)
+
Ba (s)
Complete lonic:
I
Net lonic:

Complete ionic: 2Cr(3+) + 6(NO3)- + 3Ba = 2Cr + 3Ba(2+) + 6(NO3)-

Net ionic; 2Cr(3+) + 3Ba = 2Cr + 3Ba(2+)

Explanation:

We are given;

Cr(NO3)3 (aq) + Ba (s)

Let's first find the product of this reaction before getting the complete and net ionic equations.

2Cr(NO3)3 + 3Ba = 2Cr + 3Ba(NO3)2

The complete ionic equation will be;

2Cr(3+) + 6(NO3)- + 3Ba = 2Cr + 3Ba(2+) + 6(NO3)-

The net ionic equation is gotten by eliminating the spectator ions from both left and right hand sides of the equation.

Thus, net ionic equation is;

2Cr(3+) + 3Ba = 2Cr + 3Ba(2+)

- lead + phosphoric acid = hydrogen + lead(ii) phosphate