Use the following balanced reaction to solve 1-3: P4 (s) + 6H2 (g) → 4PH3 (g)

How many grams of phosphorus trihydride will be formed by reacting 60 L of Hydrogen gas with an excess of P4?

60.86 g of PH₃

Explanation:

We'll begin by calculating the number of mole of H₂ that will occupy 60 L. This can be obtained as follow:

22.4 L = 1 mole of H₂

Therefore,

60 L = 60 / 22.4

60 L = 2.68 mole of H₂.

Next, we shall determine the number of mole of PH₃ produced by the reaction of 60 L (i.e 2.68 mole) of H₂. This can be obtained as follow:

P₄ + 6H₂ –> 4PH₃

From the balanced equation above,

6 moles of H₂ reacted to produce 4 moles of PH₃.

Therefore, 2.68 moles of H₂ will react to to produce = (2.68 × 4)/6 = 1.79 moles of PH₃.

Finally, we shall determine the mass of 1.79 moles of PH₃. This can be obtained as follow:

Mole of PH₃ = 1.79 moles

Molar mass of PH₃ = 31 + (3×1)

= 31 + 3 = 34 g/mol

Mass of PH₃ =?

Mass = mole × molar mass

Mass of PH₃ = 1.79 × 34

Mass of PH₃ = 60.86 g

Thus, 60.86 g of PH₃ were obtained from the reaction.

the answer is b & c i believe : )

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