What is the total number of grams of solute in 500 milliliters of 1M CH3COOH (formula mass = 60)?​

30 grams

Explanation:

Molarity of a solution represents its molar concentration, and can be calculated by using the formula as follows:

Molarity (M) = number of moles (n) ÷ volume (V)

Based on the information provided, volume of solution = 500 milliliters, molarity = 1M

Volume of solution in liters = 500mL ÷ 1000 = 0.50L

Molarity = n/V

1 = n/0.50

n = 0.50moles

Using mole = mass/molar mass

Molar mass of CH3COOH (acetic acid) = 60g/mol

Mass = mole × molar mass

mass = 0.50 × 60

mass = 30 grams.