How many liters of water are needed to make 6.3 M solution of NaCl made with 5,128 grams of Na Cl (molar mass = 58)?

0.014 Liters needed

Explanation:

Given 5.128 grams NaCl + ?Water Solvent => 6.3M solution

Solution Concentration = moles solute/liter solution = Molarity (M)

=> Molarity (M) = 6.3M = (5.128g NaCl/58g·mole⁻¹) / Volume of Sol'n (L)

∴ Vol of Solution = Vol of Water Solvent needed

= (5.128g NaCl/58g·mole⁻¹) / 6.3M

= 0.0884 mole NaCl / 6.3 mol/L = 0.014 Liters water solvent.

Method of Mixing:

Transfer 5.128g NaCl into mixing container and add solvent water up to but not to exceed 0.014 Liters (=14 ml) total volume. Mix till homogeneous.

increased stability in the completion of fluorine's outer shell.

your answer would be “dry”