An 85.00 g sample of an unknown compound contains 24.26 g molybdenum, 24.33 g sulfur, and the rest is oxygen. How many moles of molybdenum are present in the compound

A) 0.253 mol B) 0.7603 mol C) 2.276 mol D) MoS₃O₉ or Mo(SO₃)₃ E) molybdenum(VI) sulfite

Explanation:

For all the Mole problems you want to find divide grams of the element in compound by the molar mass of the element.

24.26 g Mo / 95.95 g = 0.2528

24.33 g S / 32.06 g = 0.7589 mol S

36.41 g O / 16 g = 2.276 mol O

S /  Mo =  0.7587 mol  / 0.2529 mol  =  3/ 1

O / Mo =  2.276 mol  / 0.2529 mol  =  9/ 1

The empirical formula of the compound is MoS₃O₉ or Mo(SO₃)₃.

thats how its supposed to be

explanation:

two years ago, when picking flowers in the mountains back of yosemite valley, i found a book. it was blotted and storm-beaten; all of its outer pages were mealy and crumbly. the paper seemed to dissolve like the snow beneath which it had been buried, however; many of the inner pages were well preserved. and although all were more or less stained and torn, whole chapters were easily readable. this is the condition of the great open book of yosemite glaciers today; its granite pages have been torn and blurred by the same storms that wasted the castaway book.

two years ago, when picking flowers in the mountains back of yosemite valley; i found a book. it was blotted and storm-beaten, all of its outer pages were mealy and crumbly. the paper seemed to dissolve like the snow beneath which it had been buried, however, many of the inner pages were well preserved. and although all were more or less stained and torn; whole chapters were easily readable. this is the condition of the great open book of yosemite glaciers today, its granite pages have been torn and blurred by the same storms that wasted the castaway book.