For the reaction 2 Al + 3 H2SO4⟶ 3 H2 + H2(SO4)3 how many grams of sulfuric acid, H2SO4, are needed to react completely with 53.7 g of aluminum, Al??

292.4 g

Explanation:

First we convert 53.7 g of Al into moles, using its molar mass:

Then we convert Al moles into H₂SO₄ moles, using the stoichiometric coefficients:

Finally we convert 2.98 moles of sulfuric acid into grams, using its molar mass:

that's just how they are

explanation:

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> b takes place in the gas phase in an isothermal tubular reactor. the feed is one mole of a per one mole of c, an inert. the entering temperature and pressure are 427°c and 10 atm, respectively. the gas constant r = 0.08206 atm · l/mol · k.