A 10.0 g sample of salt was dissolved in 200.0 g water. The temperature rose by 3.50 °C. Assume the solution has the same specific heat as water 4.184 J/g°C. Use both the mass of water and salt for your calculation.

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :

the correct answer would be b) volume versus temperature, because they are also directly proportional.

i only know number one that’s a galaxy