What is the specific heat capacity of a 70 g sample of an unknown metal that releases 6700J of heat when it cools from 90 to 25 degrees C?

Q = mCpΔT —> Solve for Cp —> Cp = q/mΔT

q = -6700 J (negative because it released heat
m = 70 g
ΔT = Final temp - initial temp = 25 - 90 = -65°C

Cp = -6700 J / (70 g)(-65°C) = 1.47 J/g°C

It's either 3 or that ,,but if not than choose 4

The density would be 1.622