Na2CO3(aq) + CaCl2(aq) > 2 NaCl(aq) + CaCO3(s) calculate the volume (in mL) of 0.100M CaCl2 needed to produce 1.00g of CaCO3(s)
There is an excess of Na2CO3.

molar mass of calcium carbonate = 100.09 g/mol

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