3. Calculate the energy in joules) of a photon with a wavelength of 3.66 X 104 hm (Infrared region) (Hint: Use Planck's equation) 104.3 x 10")
104.3 x 10-21,
1.043 X 1033
5.43 x 10 21

5.43×10¯³² J

Explanation:

From the question given above, the following data were obtained:

Wavelength (λ) = 3.66×10⁴ hm

Energy (E) =?

Next, we shall convert 3.66×10⁴ hm to metre (m). This can be obtained as follow:

1 hm = 100 m

Therefore,

3.66×10⁴ hm = 3.66×10⁴ hm × 100 m / 1 hm

3.66×10⁴ hm = 3.66×10⁶ m

Next, we shall determine the frequency of the frequency of the photon. This can be obtained as follow:

Wavelength (λ) = 3.66×10⁶ m

Velocity (v) = 3×10⁸ m/s

Frequency (f) =?

v = λf

3×10⁸ = 3.66×10⁶ × f

Divide both side by 3.66×10⁶

f = 3×10⁸ / 3.66×10⁶

f = 81.97 Hz

Finally, we shall determine the energy of the photon. This can be obtained as follow:

Frequency (f) = 81.97 Hz

Planck's constant (h) = 6.63×10¯³⁴ Js

Energy (E) =?

E = hf

E = 6.63×10¯³⁴ × 81.97

E = 5.43×10¯³² J

Therefore, the energy of the photon is 5.43×10¯³² J

idk what the question is about