A compound consists of 14.6% carbon and 85.4% chlorine by mass. What is its empirical formula?

Explanation:

When calculating an empirical formula from percentages, assume you have a 100g sample. This allows you to convert the percentages directly to grams, because X % of 100g is X grams.

So:

14.6% C = 14.6g C, 85.4%Cl = 85.4g Cl

The next step is to divide each mass by their molar mass to convert your grams to moles.

14.6g/12.01 = 1.22 mol

85.4g/35.45= 2.41 mol

Then you will divide all of your mol values by the SMALLEST number of moles. This gives you whole numbers that are the mole ratio (subscripts) of the empirical formula.

1.22 mol/1.22 mol = 1

2.41 mol/1.22 mol = 2

So the empirical formula is

it is to be noted that an alpha particle is an helium nucleus. so it contains 2 protons 2 neutrons and has a mass number of 4. when alpha decay particles are ejected from the nucleus it gets transformed into an atom which has atomic number less than 2 and a mass number less than 4.

an equation that could represent alpha decay is radium 226 decay of alpha particle forms radon 222.

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