How many moles of C6H12O6 will be produced if 22 grams of CO2 are reacted

60 grams

Explanation:

We have the balanced equation (without state symbols):

6

H

2

O

+

6

C

O

2

→

C

6

H

12

O

6

+

6

O

2

So, we would need six moles of carbon dioxide to fully produce one mole of glucose.

Here, we got  

88

g

of carbon dioxide, and we need to convert it into moles.

Carbon dioxide has a molar mass of  

44

g/mol

. So here, there exist

88

g

44

g

/mol

=

2

mol

Since there are two moles of  

C

O

2

, we can produce  

2

6

⋅

1

=

1

3

moles of glucose  

(

C

6

H

12

O

6

)

.

We need to find the mass of the glucose produced, so we multiply the number of moles of glucose by its molar mass.

Glucose has a molar mass of  

180.156

g/mol

. So here, the mass of glucose produced is

1

3

mol

⋅

180.156

g

mol

≈

60

g

to the nearest whole number.

So, approximately  

60

grams of glucose will be produced.