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Chemistry, 26.03.2021 17:20, madisynk78
I
NEN + 3 H-H → 2 H-N
H
H-H 436 kJ/mol
H-N 391 kJ/mol
N=N 914 kJ/mol
Calculate the AH for the reaction above using the given bond energies.
O-124 kJ/mol
0 -97 kJ/mol
O 959 kJ/mol
O 177 kJ/mol
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Answers: 1
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Do you know the correct answer?
I
NEN + 3 H-H → 2 H-N
H
H-H 436 kJ/mol
H-N 391 kJ/mol
N=N 914 kJ/mol
...
H
H-H 436 kJ/mol
H-N 391 kJ/mol
N=N 914 kJ/mol
...
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