The mass of the Na2CO3 in the test tube after the reaction in Part A of the
experiment is 0.8906 g. The theoretical yield is 0.9874 g. Find percent yield for this
reaction. Write only the number, not the % symbol.
4
(NaHCO3 = 84.01 g/mol, Na2CO3 = 105.99 g/mol)
2NaHCO3(s)
Na2CO3(s) + CO2(g) + H2O(g)
Answers: 3
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The mass of the Na2CO3 in the test tube after the reaction in Part A of the
experiment is 0.8906 g....
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