The number of grams of sulfur in 223 grams of sodium sulfate is . . . Grams And explain how, I still dont get it fully

50.25 g of sulphur, S.

Explanation:

Mass of Na₂SO₄ = 223 g

Mass of sulphur =?

Next we shall determine the molar mass of Na₂SO₄. This can be obtained as follow:

Molar mass of Na₂SO₄ = (23×2) + 32 + (16×4)

= 46 + 32 +64

= 142 g/mol

Mass of S in 142 g of Na₂SO₄ = 32 g

Finally, we shall determine the mass of S in 223 g of Na₂SO₄. This can be obtained as follow:

142 g of Na₂SO₄ contains 32 g of S.

Therefore, 223 g of Na₂SO₄ will contain = (223 × 32) / 142 = 50.25 g of S.

Thus, 223 g of sodium sulfate, Na₂SO₄ contains 50.25 g of sulphur, S.

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