A weather balloon with a volume of 250.0 L is released in Houston when the pressure is 102.6 kPa and 37.2 degrees Celsius. What will the volume of the balloon be after the balloon reaches am altitude of 6000 m where the pressure is 48.55 kPa and the temperature is 3.10 degrees Celsius

470.24 L

Explanation:

Initial Volume, V1 = 250 L

Initial Pressure P1 = 102.6 kPa

Initial Temperature, T1 = 37.2  + 273 = 310.2 K

Final Pressure, P2 = 48.55 kPa

Final Temperature, T2 = 3.10 + 273 = 276.1 K

Final Volume,V2 = ?

These quantites are related by the general gas equation;

P1V11 / T1  = P2V2 / T2

Solving for V2;

V2 = P1 V1 T2  / P2 T1

V2 = 102.6 * 250 * 276.1 / (48.55 * 310.2)

V2 = 470.24 L