Chemistry, 23.03.2021 20:20, khorasanpublic
4NH3(g) + 5O2(g) -> 4NO(g) + 6H2O(g)
How many moles of ammonia (NH3) are needed if 2.75 moles of water (H2O) were produced?
4.13 mol
1.83 mol
4 mol
(only respond if you have the answer)
6.8 mol
Answers: 1
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4NH3(g) + 5O2(g) -> 4NO(g) + 6H2O(g)
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