Determine the molarity of a solution formed by dissolving 0.968 g of MgCl2in enough water to yield 150.0 mL of solution.

M = 0.0678 M

Explanation:

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In this case, since the molarity of a solution is obtained by dividing the moles by the volume, it is firstly necessary to compute the moles of magnesium chloride in 0.968 g, via its molar mass, as shown below:

Next, since 150.0 mL in liters is 0.1500 L, according to the appropriate units, the resulting molarity is:

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answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :