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Chemistry, 22.03.2021 20:00, shelbymelton18
A 3.152 g sample of a solid mixture was analyzed for barium ion. First the rock was crushed in a mortar and pestle. 100% of the sample was transferred to a beaker, where it was dissolved in 150.0 mL of d. i. water. to give 152 mL of solution. The aqueous sample was then analyzed by adding a small excess of sulfuric acid. The resultant reaction produced a precipitate of barium sulfate, which was collected by filtration, rinsed, dried and weighed. If 0.4937 g of barium sulfate was obtained, 1) what was the mass percent of barium in the original sample
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A 3.152 g sample of a solid mixture was analyzed for barium ion. First the rock was crushed in a mor...
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