In a victor Mayer's experiment 0.33g of organic liquid of molecular weight 120g/mol was vaporized at 293k and 1.013 *10 N/ m calculate the vol in cm3 of air displaced

66.13 cm³

Explanation:

Using the ideal gas equation, PV = mRT/M where P = pressure = 1.013 × 10⁵ N/m², V = volume of liquid vaporized = volume of air displaced, m = mass of organic liquid = 0.33 g, M = molar mass of gas = 120 g/mol and R = molar gas constant = 8.314 J/mol-K and T = temperature at vaporization = 293 K.

PV = mRT/M

So, V = mRT/PM

Substituting the values of the variables into the equation, we have

V = 0.33 g × 8.314 J/mol-K × 293 K/(1.013 × 10⁵ N/m² × 120 g/mol)

V = 803.881/121.56 × 10⁻⁵ m³

V = 6.613 × 10⁻⁵ m³

V = 6.613 × 10⁻⁵ × 1m³

V = 6.613 × 10⁻⁵ × 10⁶ cm³

V = 6.613 × 10 cm³

V = 66.13 cm³

for step 7 table c on the lab "newtons law of action"   the average time it took the car to travel .25 meters   was 1.92 seconds.

the average time it took the car to travel 0.50 meters was 2.61 seconds

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