A physician orders 0.6 L of an 8% (m/v) solution of a drug in aqueous solution. The pharmacy has 300 mL of a 10 % (m/v) solution of this drug on hand. What volume of this solution would be needed to prepare the prescriptio

The volume of the solution the pharmacy needs to prepare the prescription is 480 mL

Explanation:

The volume of the drug the physician orders = 0.6 L = 600 mL

The concentration of the drug the physician ordered = 8% (m/v)

The volume of the drug the pharmacy has = 300 mL

The concentration of the drug the pharmacy has = 10% (m/v)

Therefore;

The mass of the drug the physician ordered, m₁ = 600 × 8% = 48 g

The mass of the drug the pharmacy has, m₂ = 300 × 10% = 30 g

The mass of the drug the pharmacy needs = 48 g - 30 g = 18 g

The volume of the solution that needs to be added, Vₐ = 18 g/(10%) = 180 mL

Therefore, the volume of the solution the pharmacy needs to prepare the prescription, 'V', is given as follows;

V = Vₐ + 300 mL

V = 180 mL + 300 mL = 480 mL

The volume of the solution the pharmacy needs to prepare the prescription, V = 480 mL

lol idk man i guess u gotta ask bill nye the science guy