Given the decomposition of hydrogen peroxide, calculate the moles of oxygen gas produced from 4.20 mol of H2O2. 2H2O2(l)→2H2O(l)+O2(g)

2.10 moles of O₂

Explanation:

2 H₂O₂ (l) → 2H₂O(l)  + O₂(g)

In this reaction we say, that 2 moles of hydrogen peroxide can decompose to 2 moles of water and 1 mol of oyxgen.

So ratio is 2:1, according to stoichiometry.

If we apply a rule of three;

2 moles of hydrogen peroxide can decompose to 1 mol of oxygen

Then 4.20 moles of hydrogen peroxide may produced (4.20 . 1)/2 =

2.10 moles of O₂

h let me think

the answer is c i believe