Finally, what mass of Na2HPO4 is required? Again, assume a 1.00 L volume buffer solution. Target pH = 7.49 Acid/Base pair: NaH2PO4 Na2HPO4 PK = 7.21 [Na2HPO4] > [NaH2PO4] (NaH2PO4) = 0.100 M 12.0 g NaH2PO4 required [base] [acid] = 1.91 [Na2HPO4) = 0.191 M. There is 1.00 L of solution. Use the molar mass of the base (141.95 g/mol)to find the mass required. Cubmit Answer Try Another Version 3 item attempts remaining Help Would Be Much Obliged! ​

vanderwaal's forces of attraction are the electrostatic intermolecular forces that exist in a molecule due to the temporary or permanent dipoles that are developed in a molecule. in , the major intermolecular forces are dipole-dipole interactions as the molecule is polar (bent structure). so the vanderwaal's forces of interaction in between molecules are the permanent dipole-dipole interactions that develop due to the dipole that exists in between the polar h - s bond. the positively charged hydrogen atom is attracted towards the negative end of the dipole that is sulfur of the adjacent molecule. therefore, these forces of attraction are relatively stronger than that of london dispersion forces that exist in non polar molecules.

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the answer is 0.8m.

by: nicholas