A compound contains 0.5 mol Na, 0.5 mol N, and 10 mol H. The empirical formula of the compound is -

NaNH₂₀

Explanation:

0.5 mol Na, 0.5 mol N, and 10 mol H

To obtain the empirical formulae, we find the mole ratio between the elements and this is done by dividing all through by the smallest mol (0.5)

Na = 0.5 / 0.5 = 1

N = 0.5 / 0.5 = 1

H = 10 / 0.5 = 20

The mole ratio is used to write the empirical formulae. It is given as;

NaNH₂₀

that's what i got you can count the number of atoms

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. completely dissociates to and ions. a is incorrect because does not fully ionize to and ions and some remain as the compound . c and d are incorrect because, and do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both and have a complete octet so can not accept any electrons which disqualifies them as acids.