2Na + 2H20 – 2NaOH+H2 How many Liters of water are needed if 3.7 moles of Hydrogen are available?

0.1332 L

Explanation:

The balanced chemical equation is the following:

2 Na(s) + 2 H₂O(l) → 2 NaOH(aq) + H₂(g)

According to the equation, 2 moles of water (H₂O) produce 1 mol of hydrogen (H₂). So, the stoichiometric ratio is 1 mol H₂/2 mol H₂O. To calculate how many moles of H₂O we need to produce 3.7 moles of H₂, we multiply the moles by the stoichiometric ratio:

3.7 moles H₂ x 2 mol H₂O/1 mol H₂ = 7.4 moles H₂O

Now, we have to convert the moles of water to liters. For this, we have to consider the molecular weight (MW) of water and its density (let's consider 1.0 g/mL).

MW(H₂O) = (2 x 1 g/mol H) + 16 g/mol = 18 g/mol

7.4 moles H₂O x 18 g/mol = 133.2 g

133.2 g/(1.0 g/ml) = 133.2 mL

133.2 ml x 1 L/1000 ml = 0.1332 L

Therefore, approximately 0.13 liters of water are needed.