For the reaction C2H2(g) + 3 O2(g) – 2 CO2(g) + 2 H2O(g)
What number of grams of CO2 could be produced from 2.0 g of C2H4 and 5.0 g of O2?

3.3792 g

Explanation:

The balanced equation for the reaction is given as;

2 C2H2(g) + 3 O2(g) --> 2 CO2(g) + 2 H2O(g)

From the reaction;

2 mol of C2H2 requires 3 mol of O2

2.0 g of C2H2

Number of moles = Mass / Molar mass = 2 / 26.04 = 0.07680 mol

5.0 g of O2

Number of moles = Mass / Molar mass = 5 / 32 = 0.15625 mol

The limiting reactant is; C2H2

2 mol of C2H2 produces 2 mol of CO2

0.07680 mol produces x

Solving for x;

x = 0.07680 mol

Mass = Molar mass * Number of moles = 44 g/mol * 0.07680 mol = 3.3792 g

linda: 3 ; laura: 15

step-by-step explanation:

note that linda + laura's age is 18, and that linda is 12 years younger than her sister.

let "linda" = x , "laura" = y:

x + y = 18

x = y - 12

first, plug in y - 12 for x in the first equation:

(y - 12) + y = 18

simplify.

2y - 12 = 18

isolate the variable (y). note the equal sign, what you do to one side, you do to the other. do the opposite of pemdas. first add, then divide.

2y - 12 (+12) = 18 (+12)

2y = 18 + 12

2y = 30

(2y)/2 = (30)/2

y = 30/2

y = 15

next, plug in 15 for y in the second equation (the other equation would work too).

x = y - 12

x = (15) - 12

x = 3

linda's age is 3, laura's age is 15.

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