Saline is a 0,154 M NaCl solution. If the mass of NaCl is used to prepare saline solution was 45,045 grams, find the volume of solution that was obtained.
(Na:23; Cl:35,5)

The volume of solution is 200 ml

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

where,

n = moles of solute

= volume of solution in ml

moles of =

Now put all the given values in the formula of molality, we get

Therefore, the volume of solution is 200 ml

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm