HNO3 + H2SO4 + NO You now have these half-reaction equations:
3e + HNO3 → NO
S→ H2SO4 + 6e
Which factor will you use for the top equation?
Which factor will you use for the bottom equation?

Explanation:

The two half equations are;

3e + HNO3 → NO

S→ H2SO4 + 6e

When balancing half equations, we have to make sure the number of electrons gained is equal to the number of electrons lost.

Which factor will you use for the top equation?

We multiply by 2 to make the number of electrons =  6e

Which factor will you use for the bottom equation?

We multiply by 1 to make the number of electrons = 6e

more info ? ? i don't understand what the question is

explanation:

vanderwaal's forces of attraction are the electrostatic intermolecular forces that exist in a molecule due to the temporary or permanent dipoles that are developed in a molecule. in , the major intermolecular forces are dipole-dipole interactions as the molecule is polar (bent structure). so the vanderwaal's forces of interaction in between molecules are the permanent dipole-dipole interactions that develop due to the dipole that exists in between the polar h - s bond. the positively charged hydrogen atom is attracted towards the negative end of the dipole that is sulfur of the adjacent molecule. therefore, these forces of attraction are relatively stronger than that of london dispersion forces that exist in non polar molecules.