SHOW ALL WORK AND INCLUDE UNITS How many kilojoules of heat are released when 0.72 mole of oxygen gas are used to combust methane?
CH4 (g) + 2O2 (g) → CO2 (g) + 2H2O (ℓ) + 890kJ

0.72 mole of oxygen would produce 320.4 kJ of heat.

Explanation:

CH₄ (g) + 2O₂ (g) → CO₂ (g) + 2H₂O (ℓ) + 890kJ

According to the equation,

2 moles of O₂ produces 890 kJ of heat

So, 0.72 moles of O₂ will produce:

Therefore, 0.72 moles of oxygen would produce 320.4 kJ of heat.

the awnser is group 12

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole