9.32 L of pentane reacts with 36.4 L of oxygen. how many liters of carbon dioxide are formed?

22.75 L CO2

Explanation:

Balance the Equation

C5H12  +  O2 ==>   CO2 + H2O        Balance the Carbons

C5H12  +  O2 ==>   5CO2 + H2O     Now balance the Hydrogens

C5H12  +  O2 ==>   5CO2 + 6H2O   Now count up the oxygens on the right.

5*O2 + 6O ==> 10 O + 6 O ===> 16 Oxygens.

You have 2 on the left. You have to multiply the oxygens by 8

C5H12  +  8O2 ==>   5CO2 + 6 H2O

The equation is now balanced.

Now find out how much oxygen is needed to burn 9.32 L of Pentane

1 Liter Pentane / 8 Liters Oxygen = 9.32 L Pentane / x     Cross multiply

x = 8 * 9.32

x = 74.56

Read this next sentence very carefully. You need 74.56 Liters of oxygen to burn all the pentane you have. There's not that much there. You only have 36.4 Liters of Oxygen. Some of the pentane won't get burned. Consequently there will be a shortage of CO2 as well.

Find out the number of Liters of Pentane that will be burned up.

1 / x =  8 / 36.4               Cross multiply

8x = 36.4                        Divide by 8

8x/8 = 36.4/8

x = 4.55 Liters of Pentane will be  used up.

Find the number of Liters of CO2

For every Liter of Pentane, 5 Liters of CO2 will be produced.

1/5 = 4.55/x                      Cross Multiply

x = 5 * 4.55

x = 22.75

the volume increases