How many grams of Oz would be needed to produce 1.875 moles of aluminum? 4 AI + 3 O2 -> 2Al2O3

1.4063 moles of oxygen are required

Explanation:

Based on the chemical equation:

4Al + 3O₂ → 2Al₂O₃

4 moles of aluminium react with 3 moles of oxygen.

To solve this question we need to convert the moles of aluminium to moles of oxygen using the chemical reaction:

1.875 moles Al * (3 moles O₂ / 4 moles Al) =