Calculate the energy in joules to heat 171 g of mercury from 37.0◦ C to 42.0◦ C. The specific
heat capacity of Hg(ℓ) is 0.139 J/g· ◦C.

Explanation:

There is 575.46 J of heat released

Explanation:

Step 1: Data given

Mass of mercury = 828 grams

Heat capacity of mercury = 0.139J/g°C

Initial temperature = 37.0°C

Final temperature = 42.0 °C

Step 2: Calculate heat released

Q = m*c*ΔT

⇒ Q =the heat released in Joule

⇒ m = the mass of mercury = 828 grams

⇒ c = the heat capacity of mercury = 0.139 J/g°C

⇒ ΔT = the change of temperature = T2 - T1 = 42.0 - 37.0 = 5.0 °C

Q = 828 g * 0.139 J/g°C * 5.0 °C

Q = 575.46 J

There is 575.46 J of heat released

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the enthalpy of formation of water is given as -285.8kj/mol, which states that the enthalpy of formation is negative.

negative enthalpy of formation indicates that the heat is released during the reaction process. the heat is released from reaction to the surroundings the enthalpy is expressed with a negative sign with the energy given out in the reaction process.

the formation of water takes place by giving out heat which is -285.8 kj/mol.