What happens to the electrode potential when zn2+ increase in concentration. Using the half equation Zn2+ + 2e- > Zn​

201cm/s÷5: 18

explanation:

there is no explanation

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer

catya that's not even a b or c