If the initial rate of H2 to disappear is 2.0 moles per second, what is the rate of appearance of NH3 at the same time? N2(g) 3 H2(g) ⇌ 2 NH3(g)

1.33 moles per second

Explanation:

From the balanced equation of reaction, 3 moles of H2(g) need to disappear/be consumed before 2 moles of NH3(g) can be formed/appear.

According to reaction law, the rate of disappearance of reactants is equal to the rate of appearance of products.

Now, only 2 moles per seconds of H2 has disappeared initially;

3 moles H2 is needed for 2 moles NH3

2 moles H2 will give;        2 x 2/3 = 4/3 or 1.33 moles

Hence, if the initial rate of disappearance of H2 is 2.0 moles per second, the initial rate of appearance of NH3 would be 1.33 moles per second.

it’s previous models   because when i picked that son of a gun’s answer it was wrong look for previous models because they might make it a different letter