What is the volume, in liters, of 5.500 mol of C3H3 gas at STP

123.2 Liters.

Explanation:

At STP (T = 273K & P = 1atm), one mol of any gas will occupy 22.4 liters.

With the above information in mind, we can calculate how many liters would 5.500 mol of gas occupy:

5.500 mol * 22.4 L / mol = 123.2 L

So 5.500 moles of C₃H₃ would have a volume of 123.2 liters at STP.

the answer would be b i believe