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Chemistry, 12.03.2021 22:00, Michael321
How would i set this up to find specific heat capacity (c) of copper? (Cu)
mH20 × cH20 × (ΔT H20) = -(m Cu × C Cu × (ΔT Cu))
100g × 4.184 (j/g °C) × (23.52 °C - 20 °C) = -(50g × c cu × (23.52 °C - 100 °C))
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How would i set this up to find specific heat capacity (c) of copper? (Cu)
mH20 × cH20 × (ΔT H20) =...
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