M H20 × c H20 × (ΔT h20) = -(m Cu × c Cu × (ΔT Cu)) 100g × 4.184 (j/g °C) × (23.52 °C - 20 °C) = -(50g × c cu× (23.52 °C - 100 °C))
how would i set this up find specific heat capasity (c) of copper? (Cu)

If i can still dissolve more sugar into the solution at a certain temperature what would i call that solution

Plz mark brainliest 30 points 1) find the momentum of a 12 kg snowball that is rolling with a velocity of 9 m/s. 2) an 8 ball with a mass of .5 kg is sitting at rest. it is hit by the cue ball (1 kg) traveling at 2.5 m/s. if the cue ball is at rest after the collision, how fast is the 8 ball traveling after the collision? 3) two football players are running toward each other. if the offensive player is 75 kg and is running 8 m/s, how fast must the 60 kg defensive player run in order for the two players to hit and stop?

If two atoms are bonded to a central atom with no lone pairs, how will they be arranged